This notebook describes the epsilon mechanism by which numerical singularities are handled in SymForce. The paper addresses the theory in Section VI, and this tutorial demonstrates the idea through examples.
The basic concept is that it is common to have functions in robotics that are smooth but have singularities at given points. Handwritten functions tend to handle them by adding an if statement at the singularity with some kind of approximation or alternate formulation. This is harder to do with symbolic expressions, and also is not kind to branch prediction. SymForce addresses this with a different method - shifting the input to the function away from the singular point with an infinitesimal variable \(\epsilon\) (epsilon). This approach is simple and fast for a useful class of removable singularities, with negligible effect to output values for sufficiently small epsilon.
All functions in SymForce that have singularities take epsilon as an argument. In a numerical context, a very small floating point number should be passed in. In the symbolic context, an epsilon symbol should be passed in. Epsilon arguments are currently optional with zero defaults. This is convenient so that playing with expressions in a notebook doesn’t require passing epsilons around. However, this is dangerous and it is extremely important to pass epsilons to get robust behavior or when generating code. Because of this, there are active efforts to make a more intelligent mechanism for the default epsilon to make it less of a footgun to accidentally forget an epsilon and end up with a NaN.
We have a function
In the simplest case, we’re trying to fix a removable singularity at
f(x).subs(x, 0) == sm.S.NaN
Libraries often do this by checking whether the value of
x is close to 0, and using a different method for evaluation there, such as a Taylor expansion. In symbolic expressions, branching like this is messy and expensive.
f(x, eps)so the value is not NaN, when
epsis a small positive number:
f(x, eps).subs(x, 0) != sm.S.NaN
f(x, eps).diff(x).subs(x, 0) != NaN
f(x, eps).subs(x, 0).limit(eps, 0) == f(x).limit(x, 0)
For derivative continuity we want to match the limit:
f(x, eps).diff(x).subs(x, 0).limit(eps, 0) == f(x).diff(x).limit(x, 0)
import numpy as np import plotly.express as px import sympy as sm x = sm.Symbol("x") eps = sm.Symbol("epsilon")
An example: sin(x) / x¶
For the whole section below, let’s pretend x is positive so \(x = -\epsilon\) is not a fear. We’ll address that later.
# The function `sin(x) / x` looks like this: def f(x): return sm.sin(x) / x f(x)
# And its graph: x_numerical = np.linspace(-5, 5) px.line(x=x_numerical, y=np.vectorize(f, otypes=[float])(x_numerical))